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如何使用 sql (mysql)查询任意两条重复的记录?

SELECT* , SUM(num) as '总数'FROMtd_textWHERENAME IN ( SELECT NAME FROM td_text GROUP BY NAME HAVING count(NAME) > 1 )GROUP BY `name`td_text 表数据: 执行sql后

select * from 用户表 where 用户名 in (select 用户名 from 用户表 group by 用户名 having count(1)>1)

selectt1.id,t1.from_uid,t2.name as from_name,t1.to_uid,t3.name as to_name,t1.contentfromchat t1,user t2,user t3where 1=1and t1.from_uid = t2.idand t1.to_uid = t3.idand t2.name in ('张三', '李四')and t3.name in ('张三', '李四')...

两种方法,一种是查询重复的数据,只查询重复记录,不管其余信息,如ID什么的: select uid, time from ztest GROUP BY uid, time having count(*)>1;查出结果是 uid time 1 1 还有一种是查询你指定信息,可以查询出ID信息: select distinct a....

上面的回答可以,不过我觉得还有更简单的方法: select aid, count(distinct uid) from 表名 group by aid 这是sqlserver 的写法。。。

可用group by……having来实现。 可做如下测试: 1、创建表插入数据: create table test(id int,name varchar(10))insert into test values (1,'张三')insert into test values (2,'李四')insert into test values (3,'张三')insert into test va...

1: SELECT * FROM `table` WHERE a=4 union ALL SELECT * FROM `table` WHERE b=4 union ALL SELECT * FROM `table` WHERE a=4 AND b=4

看一下这个SQL selectsum(if((sex = 1 and age = 2),1,0)),sum(if((sex = 1 and age = 5),1,0)),sum(if((sex = 1 and age = 10),1,0))from a_test 这个SQL现在就是得出的这个结果

查看可用如下方法: 1、创建测试表,插入数据: create table product(id int,name varchar(10),totol int)insert into product values (1,'香蕉',100)insert into product values (2,'橘子',67)insert into product values (3,'葡萄',89)insert...

不知道你的a,b两表有没有关联,假定没有关联 select count(1)from (select idfrom a where id>5union allselect id from b where id>5)

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