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SQL语句理解 sElECt * From B whErE (sElECt Count...

假设个例子吧:A表 id 姓名 性别 00 aa 女 01 bb 女 02 cc 女 B表 id 姓名 性别 00 aa 女 02 cc 女 03 dd 男 select * from B是执行B表, 当执行id=‘00’时 ,因为select count(1) as num from A where A.ID = B.ID 不等于0 所以运行结果没有第一...

select count(*) from aa where (select * from aa where a=1)错了 select count(*) from aa where a=1 select count(*) from aa where a in (select a from aa where a=1)

Mysql中可以执行,符合mysql规范,默认返回第一条记录的id 但是oracle不能执行,报ORA-00937,所以不符合oracle规范

SELECT SUM ( t.iSum ) as sum FROM ( select count(A.abc) as iSum from A left join B on A.id=B.id where A.abc='1' group by A.abc ); 或者 select count(A.abc) as sum from A left join B on A.id=B.id where A.abc='1'

select a. col1, b.col2 from (select count(id) as col1 from table1) as a, (select count(id) as col2 from table2) as b -------------这样写。

String s = "SELECT e.*,d.dname FROM emp e LEFT JOIN dept d ON d.did=e.did WHERE 1=1"; String regex = ".*(FROM.*)$"; String result = s.replaceAll(regex, "SELECT count(*) $1"); System.out.println(result); .表示任意字符,*表示0到...

Count排序语法如下: Select * from (Select Count(字段名) as 别名 from 表名 Group By 字段名) as [查询1] order by [查询1].字段 Count语句不支持where和order by,把他先整理成一个查询,再去排列筛选就好了。

select systemdate from B语句取出的结果不止一个吧?这样写不行的。除非只有一个: select top 1systemdate from B。

mysql_query返回的是true或者false吧?

select怎么写成selcet了,语句的意思是找出A中C=1的a与B中d=1的b相同 select count(*) from (select a from dbo.A where c=1 intersect select b from dbo.B where d=1) as C select distinct count(*) from (select a from dbo.A where c=1 int...

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